Henry St Seymour is located at 41.393230, -73.070549 geo coordinates. Henry St, Seymour, CT 06483 is located in Connecticut, Seymour, United States Of America.
Latitude | Longitude |
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41.393230 | -73.070549 |
DMS Latitude | DMS Longitude |
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41° 23´ 35.6280'' N | 73° 4´ 13.9764'' W |